2x^-3*4y^5*5x^2/3y^4*7x^-3

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Solution for 2x^-3*4y^5*5x^2/3y^4*7x^-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7*x^-3*((2*4*5*x^-3*x^2*y^5)/3)*y^4 = 0

280/3*x^-4*y^9 = 0 // : 280/3*y^9

x^-4 = 0

x należy do O

x belongs to the empty set

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